Titanic Roulette Strategy
The Titanic Roulette Strategy is analysed here as a six-step table sequence on one dozen: 1, 1, 2, 3, 4, 6. It stops after the first win or after six losses, but the high chance of a hit does not make the attempt profitable on average.
The selected table sequence yields +2, +1, +2, +2, +1, or +1 on a first win and −17 after six losses. A prose version ending in 7 is a different rule and must not be merged with it.
The analysed table variant
This page analyses the TABLE variant: bet one fixed dozenbetDozen1–12, 13–24 or 25–36, pays 2:1.Read full → in stakes 1, 1, 2, 3, 4, then 6 base unitsmoneyUnitThe base stake a system or a player works in. Progressions are described in units so they apply at any table.Read full →. Stop and reset to the first stake after the first win, or stop after six losses. Keeping the selected dozen fixed makes each betting spin a 12/37 hit and a 25/37 miss. Predictably changing dozens after losses does not change those probabilities.
First-win outcomes
A dozen pays 2:1, so a first win must repay the earlier misses as well as earn its current payoutmoneyPayoutWhat a winning bet returns, quoted as “X to 1” on top of the returned stake.Read full →. The table shows results in base units after all stakes already made in the attempt.
Worked example
If the selected dozen misses at 1, 1 and 2, then wins at 3, the winning dozen returns 9 units including its 3-unit stake. Total stakes were 7, so the net is +2. If all six bets lose, the stakes total 1 + 1 + 2 + 3 + 4 + 6 = 17 and the result is −17. The cap limits a single attempt; it does not guarantee a recovery.
Do not merge the seven-unit prose variant
A prose variant that uses 7 rather than 6 as the final stake is a different progressionstrategyProgressionAny rule that changes the stake based on previous results. Negative progressions raise it after losses, positive after wins.Read full →. Its last-stage win is +3 and six losses total −18. Those figures cannot be combined with the table variant’s +1 last-stage win and −17 six-loss result. Stating which sequence is being used is necessary before quoting success or recovery figures.
Risk and expectation
With a one-dozen hit probabilitymathProbabilityChance of an outcome, from 0 to 1 or 0% to 100%. One number: 1/37 = 2.70%.Read full → of 12/37, the chance of at least one hit within six bets is 90.48454176%. That frequent-hit figure omits the size of the six-loss outcome. The expected turnovermoneyTurnoverThe total amount wagered over a session or period, counting re-bet winnings. Also: handle, action.Read full → of the TABLE variant is 5.1928440859 base units per attempt, so its expected result is −0.1403471375 base units: the usual 1/37 of turnover. After a failed 17-unit cycle, doubling the base means the most profitable result in the next listed cycle is only +4 units, not instant recovery of the prior loss.
Questions
No. A hit can produce only +1 or +2 base units in the table variant, while a six-loss attempt costs 17. The probabilities and amounts together give a negative expected result.
No. Every individual dozen covers 12 of the 37 European pocketsequipmentPocketOne of the 37 numbered compartments on the rotor. Also: slot, cup.Read full → on the next spin. Changing the chosen dozen predictably does not change that probability.
Sources
- RouletteDoc, Strategy overview
- Roulette77, Strategy overview